Not Updating Sql Database August 31, 2023 Post a Comment For some reason my code isn't updating mySQL database, but it isn't reporting any errors. register.php (form) Solution 1: Here's a working sample with prepared statements, that are "better" to use generally instead of queryaction.php$con = new mysqli('localhost', 'root', '', 'dachi'); if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } if (isset($_GET['do']) && $_GET['do'] === "register") { $teamname = $_POST["teamname"]; $teamregion = $_POST["teamregion"]; $teamleader = $_POST["teamleader"]; $teammembers = $_POST["teammembers"]; $wins = 0; $loses = 0; $stmt = $con->prepare("INSERT INTO `teams` (`teamname`,`region`,`teamleader`,`teammembers`,`wins`,`loses`) VALUES (?,?,?,?,?,?)"); $stmt->bind_param('ssssii', $teamname, $teamregion, $teamleader, $teammembers, $wins, $loses); $stmt->execute(); $stmt->close(); } Copyregister.php<form class="register_form" action="action.php?do=register" method="post"> Team Name*: <inputtype="text" name="teamname" required /> Team Region*: <inputtype="text" name="teamregion" maxlength="4" required /> Team Leader*: <inputtype="text" name="teamleader" maxlength="16" required /> Team Members: <inputtype="text" name="teammembers" /> <input name="register_submit"type="submit" value="Register" /> </form> CopySolution 2: You should change:if($action=="register") { Copytoif($action=="register_submit") { CopyBecause your input has a tag name set to value register_submit not register.and change $action = $_GET['do']; to $action = $_POST['register_submit'];Solution 3: register.php (form)<form class="register_form" action="action.php?do=register" method="post"> Copyaction.php$action = $_GET['do']; Copy Share Post a Comment for "Not Updating Sql Database"
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